Base | Representation |
---|---|
bin | 101000000001011001010… |
… | …0010001100110100111011 |
3 | 201110211220000201221122001 |
4 | 1100002302202030310323 |
5 | 1210110113140330023 |
6 | 15410530330041431 |
7 | 1105254561605662 |
oct | 120026242146473 |
9 | 21424800657561 |
10 | 5500553448763 |
11 | 183085402822a |
12 | 74a064279277 |
13 | 30b913a8c1c9 |
14 | 15032a2b5dd9 |
15 | 98136c296ad |
hex | 500b288cd3b |
5500553448763 has 2 divisors, whose sum is σ = 5500553448764. Its totient is φ = 5500553448762.
The previous prime is 5500553448661. The next prime is 5500553448787. The reversal of 5500553448763 is 3678443550055.
5500553448763 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5500553448763 - 221 = 5500551351611 is a prime.
It is not a weakly prime, because it can be changed into another prime (5500553449763) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2750276724381 + 2750276724382.
It is an arithmetic number, because the mean of its divisors is an integer number (2750276724382).
Almost surely, 25500553448763 is an apocalyptic number.
5500553448763 is a deficient number, since it is larger than the sum of its proper divisors (1).
5500553448763 is an equidigital number, since it uses as much as digits as its factorization.
5500553448763 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30240000, while the sum is 55.
The spelling of 5500553448763 in words is "five trillion, five hundred billion, five hundred fifty-three million, four hundred forty-eight thousand, seven hundred sixty-three".
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