Base | Representation |
---|---|
bin | 101000000001011001010… |
… | …1000010100111110100011 |
3 | 201110211220010202112222201 |
4 | 1100002302220110332203 |
5 | 1210110114043230021 |
6 | 15410530424314031 |
7 | 1105254611345632 |
oct | 120026250247643 |
9 | 21424803675881 |
10 | 5500555055011 |
11 | 1830854a25005 |
12 | 74a064912917 |
13 | 30b914202353 |
14 | 15032a5b3519 |
15 | 98136e45591 |
hex | 500b2a14fa3 |
5500555055011 has 2 divisors, whose sum is σ = 5500555055012. Its totient is φ = 5500555055010.
The previous prime is 5500555054993. The next prime is 5500555055059. The reversal of 5500555055011 is 1105505550055.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5500555055011 - 215 = 5500555022243 is a prime.
It is a super-3 number, since 3×55005550550113 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (5500555059011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2750277527505 + 2750277527506.
It is an arithmetic number, because the mean of its divisors is an integer number (2750277527506).
Almost surely, 25500555055011 is an apocalyptic number.
5500555055011 is a deficient number, since it is larger than the sum of its proper divisors (1).
5500555055011 is an equidigital number, since it uses as much as digits as its factorization.
5500555055011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 78125, while the sum is 37.
The spelling of 5500555055011 in words is "five trillion, five hundred billion, five hundred fifty-five million, fifty-five thousand, eleven".
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