Base | Representation |
---|---|
bin | 110011001110100101… |
… | …110000110101111001 |
3 | 12020222102202200100222 |
4 | 303032211300311321 |
5 | 1400122414112213 |
6 | 41134053105425 |
7 | 3655042666631 |
oct | 631645606571 |
9 | 166872680328 |
10 | 55005613433 |
11 | 21367264561 |
12 | a7b1328275 |
13 | 5257b15674 |
14 | 293b4536c1 |
15 | 166e059808 |
hex | cce970d79 |
55005613433 has 2 divisors, whose sum is σ = 55005613434. Its totient is φ = 55005613432.
The previous prime is 55005613427. The next prime is 55005613463. The reversal of 55005613433 is 33431650055.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 52593624889 + 2411988544 = 229333^2 + 49112^2 .
It is a cyclic number.
It is not a de Polignac number, because 55005613433 - 216 = 55005547897 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 55005613393 and 55005613402.
It is not a weakly prime, because it can be changed into another prime (55005613463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27502806716 + 27502806717.
It is an arithmetic number, because the mean of its divisors is an integer number (27502806717).
Almost surely, 255005613433 is an apocalyptic number.
It is an amenable number.
55005613433 is a deficient number, since it is larger than the sum of its proper divisors (1).
55005613433 is an equidigital number, since it uses as much as digits as its factorization.
55005613433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81000, while the sum is 35.
The spelling of 55005613433 in words is "fifty-five billion, five million, six hundred thirteen thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •