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550101001103 = 2712029892993
BaseRepresentation
bin10000000000101001001…
…00110010001110001111
31221120220111002021022222
420000110210302032033
533003101324013403
61100413553325555
754513005234063
oct10002444621617
91846814067288
10550101001103
111a2329746135
128a7438668bb
133cb49ac1b64
141c8a7125aa3
15e4992c9338
hex801493238f

550101001103 has 4 divisors (see below), whose sum is σ = 552130894368. Its totient is φ = 548071107840.

The previous prime is 550101001031. The next prime is 550101001127. The reversal of 550101001103 is 301100101055.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 550101001103 - 222 = 550096806799 is a prime.

It is a super-2 number, since 2×5501010011032 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (550101001403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1014946226 + ... + 1014946767.

It is an arithmetic number, because the mean of its divisors is an integer number (138032723592).

Almost surely, 2550101001103 is an apocalyptic number.

550101001103 is a deficient number, since it is larger than the sum of its proper divisors (2029893265).

550101001103 is a wasteful number, since it uses less digits than its factorization.

550101001103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2029893264.

The product of its (nonzero) digits is 75, while the sum is 17.

Adding to 550101001103 its reverse (301100101055), we get a palindrome (851201102158).

The spelling of 550101001103 in words is "five hundred fifty billion, one hundred one million, one thousand, one hundred three".

Divisors: 1 271 2029892993 550101001103