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550101001031 is a prime number
BaseRepresentation
bin10000000000101001001…
…00110010001101000111
31221120220111002021020022
420000110210302031013
533003101324013111
61100413553325355
754513005233631
oct10002444621507
91846814067208
10550101001031
111a232974607a
128a74386685b
133cb49ac1b0a
141c8a7125a51
15e4992c92db
hex8014932347

550101001031 has 2 divisors, whose sum is σ = 550101001032. Its totient is φ = 550101001030.

The previous prime is 550101001013. The next prime is 550101001127. The reversal of 550101001031 is 130100101055.

Together with previous prime (550101001013) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-550101001031 is a prime.

It is a super-2 number, since 2×5501010010312 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (550101006031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275050500515 + 275050500516.

It is an arithmetic number, because the mean of its divisors is an integer number (275050500516).

Almost surely, 2550101001031 is an apocalyptic number.

550101001031 is a deficient number, since it is larger than the sum of its proper divisors (1).

550101001031 is an equidigital number, since it uses as much as digits as its factorization.

550101001031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 75, while the sum is 17.

Adding to 550101001031 its reverse (130100101055), we get a palindrome (680201102086).

The spelling of 550101001031 in words is "five hundred fifty billion, one hundred one million, one thousand, thirty-one".