Base | Representation |
---|---|
bin | 110011001110111010… |
… | …011110101011110011 |
3 | 12020222210222120211011 |
4 | 303032322132223303 |
5 | 1400130311402313 |
6 | 41134405331351 |
7 | 3655140105502 |
oct | 631672365363 |
9 | 166883876734 |
10 | 55011044083 |
11 | 2136a3336a6 |
12 | a7b3106b57 |
13 | 5258c97478 |
14 | 293c068839 |
15 | 166e77d93d |
hex | ccee9eaf3 |
55011044083 has 2 divisors, whose sum is σ = 55011044084. Its totient is φ = 55011044082.
The previous prime is 55011044041. The next prime is 55011044089. The reversal of 55011044083 is 38044011055.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55011044083 is a prime.
It is a super-2 number, since 2×550110440832 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (55011044089) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27505522041 + 27505522042.
It is an arithmetic number, because the mean of its divisors is an integer number (27505522042).
Almost surely, 255011044083 is an apocalyptic number.
55011044083 is a deficient number, since it is larger than the sum of its proper divisors (1).
55011044083 is an equidigital number, since it uses as much as digits as its factorization.
55011044083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9600, while the sum is 31.
The spelling of 55011044083 in words is "fifty-five billion, eleven million, forty-four thousand, eighty-three".
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