Base | Representation |
---|---|
bin | 111110100010100101001100… |
… | …0000110110111011101001011 |
3 | 2200010210001111021222110122111 |
4 | 1331011022120012313131023 |
5 | 1034101002403101034430 |
6 | 5225553144352403151 |
7 | 223605114221661436 |
oct | 17505123006673513 |
9 | 2603701437873574 |
10 | 550110553143115 |
11 | 14a311636995638 |
12 | 5184713b2464b7 |
13 | 1a7c5283084883 |
14 | 99bb6c84b481d |
15 | 438e987eb9c2a |
hex | 1f452981b774b |
550110553143115 has 32 divisors (see below), whose sum is σ = 665877440202624. Its totient is φ = 436267728122880.
The previous prime is 550110553143113. The next prime is 550110553143169. The reversal of 550110553143115 is 511341355011055.
It is not a de Polignac number, because 550110553143115 - 21 = 550110553143113 is a prime.
It is not an unprimeable number, because it can be changed into a prime (550110553143113) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3333173377 + ... + 3333338413.
It is an arithmetic number, because the mean of its divisors is an integer number (20808670006332).
Almost surely, 2550110553143115 is an apocalyptic number.
550110553143115 is a deficient number, since it is larger than the sum of its proper divisors (115766887059509).
550110553143115 is a wasteful number, since it uses less digits than its factorization.
550110553143115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 171927.
The product of its (nonzero) digits is 112500, while the sum is 40.
The spelling of 550110553143115 in words is "five hundred fifty trillion, one hundred ten billion, five hundred fifty-three million, one hundred forty-three thousand, one hundred fifteen".
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