Base | Representation |
---|---|
bin | 111110100010100101001100… |
… | …0000110110111011101001001 |
3 | 2200010210001111021222110122102 |
4 | 1331011022120012313131021 |
5 | 1034101002403101034423 |
6 | 5225553144352403145 |
7 | 223605114221661434 |
oct | 17505123006673511 |
9 | 2603701437873572 |
10 | 550110553143113 |
11 | 14a311636995636 |
12 | 5184713b2464b5 |
13 | 1a7c5283084881 |
14 | 99bb6c84b481b |
15 | 438e987eb9c28 |
hex | 1f452981b7749 |
550110553143113 has 2 divisors, whose sum is σ = 550110553143114. Its totient is φ = 550110553143112.
The previous prime is 550110553143079. The next prime is 550110553143169. The reversal of 550110553143113 is 311341355011055.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 349121863148809 + 200988689994304 = 18684803^2 + 14177048^2 .
It is a cyclic number.
It is not a de Polignac number, because 550110553143113 - 26 = 550110553143049 is a prime.
It is not a weakly prime, because it can be changed into another prime (550110553143413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275055276571556 + 275055276571557.
It is an arithmetic number, because the mean of its divisors is an integer number (275055276571557).
Almost surely, 2550110553143113 is an apocalyptic number.
It is an amenable number.
550110553143113 is a deficient number, since it is larger than the sum of its proper divisors (1).
550110553143113 is an equidigital number, since it uses as much as digits as its factorization.
550110553143113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 67500, while the sum is 38.
The spelling of 550110553143113 in words is "five hundred fifty trillion, one hundred ten billion, five hundred fifty-three million, one hundred forty-three thousand, one hundred thirteen".
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