Base | Representation |
---|---|
bin | 11001000001000011000101… |
… | …11010110010111001001111 |
3 | 21012210001120001001101002110 |
4 | 30200201202322302321033 |
5 | 24202302224240112101 |
6 | 312555551441155103 |
7 | 14405312514522024 |
oct | 1440414272627117 |
9 | 235701501041073 |
10 | 55011600707151 |
11 | 1658a31a4a4630 |
12 | 620574992ba93 |
13 | 2490757cc72aa |
14 | d8280b94d54b |
15 | 655ea0a2ccd6 |
hex | 320862eb2e4f |
55011600707151 has 32 divisors (see below), whose sum is σ = 81981638678016. Its totient is φ = 32521972608000.
The previous prime is 55011600707149. The next prime is 55011600707153. The reversal of 55011600707151 is 15170700611055.
It is an interprime number because it is at equal distance from previous prime (55011600707149) and next prime (55011600707153).
It is not a de Polignac number, because 55011600707151 - 21 = 55011600707149 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55011600707153) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5197911 + ... + 11706471.
It is an arithmetic number, because the mean of its divisors is an integer number (2561926208688).
Almost surely, 255011600707151 is an apocalyptic number.
55011600707151 is a deficient number, since it is larger than the sum of its proper divisors (26970037970865).
55011600707151 is a wasteful number, since it uses less digits than its factorization.
55011600707151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6514863.
The product of its (nonzero) digits is 36750, while the sum is 39.
The spelling of 55011600707151 in words is "fifty-five trillion, eleven billion, six hundred million, seven hundred seven thousand, one hundred fifty-one".
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