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55012530497 is a prime number
BaseRepresentation
bin110011001111000000…
…001001100101000001
312020222220210002210112
4303033000021211001
51400131201433442
641134501241105
73655155536201
oct631700114501
9166886702715
1055012530497
1121370159441
12a7b3703195
135259397bc2
14293c334401
15166e974082
hexccf009941

55012530497 has 2 divisors, whose sum is σ = 55012530498. Its totient is φ = 55012530496.

The previous prime is 55012530491. The next prime is 55012530527. The reversal of 55012530497 is 79403521055.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 31516545841 + 23495984656 = 177529^2 + 153284^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-55012530497 is a prime.

It is a super-3 number, since 3×550125304973 (a number of 33 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (55012530491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27506265248 + 27506265249.

It is an arithmetic number, because the mean of its divisors is an integer number (27506265249).

Almost surely, 255012530497 is an apocalyptic number.

It is an amenable number.

55012530497 is a deficient number, since it is larger than the sum of its proper divisors (1).

55012530497 is an equidigital number, since it uses as much as digits as its factorization.

55012530497 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 189000, while the sum is 41.

The spelling of 55012530497 in words is "fifty-five billion, twelve million, five hundred thirty thousand, four hundred ninety-seven".