Base | Representation |
---|---|
bin | 101000000001110000000… |
… | …0111001110110101101111 |
3 | 201110220212022121211112102 |
4 | 1100003200013032311233 |
5 | 1210113144420143210 |
6 | 15411134243525315 |
7 | 1105312535365265 |
oct | 120034007166557 |
9 | 21426768554472 |
10 | 5501318131055 |
11 | 183110673636a |
12 | 74a23838983b |
13 | 30ba06327836 |
14 | 15039da8a435 |
15 | 9817de26ea5 |
hex | 500e01ced6f |
5501318131055 has 16 divisors (see below), whose sum is σ = 6653215821600. Its totient is φ = 4366696935552.
The previous prime is 5501318131027. The next prime is 5501318131063.
5501318131055 is nontrivially palindromic in base 10.
It is a cyclic number.
It is not a de Polignac number, because 5501318131055 - 28 = 5501318130799 is a prime.
It is a super-3 number, since 3×55013181310553 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3395024 + ... + 4746453.
It is an arithmetic number, because the mean of its divisors is an integer number (415825988850).
Almost surely, 25501318131055 is an apocalyptic number.
5501318131055 is a deficient number, since it is larger than the sum of its proper divisors (1151897690545).
5501318131055 is a wasteful number, since it uses less digits than its factorization.
5501318131055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8142538.
The product of its (nonzero) digits is 45000, while the sum is 38.
The spelling of 5501318131055 in words is "five trillion, five hundred one billion, three hundred eighteen million, one hundred thirty-one thousand, fifty-five".
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