Base | Representation |
---|---|
bin | 11001000001001011110000… |
… | …10110100000100101111111 |
3 | 21012210111120102102012200210 |
4 | 30200211320112200211333 |
5 | 24202341242321323210 |
6 | 313002041352323503 |
7 | 14405536043550024 |
oct | 1440457026404577 |
9 | 235714512365623 |
10 | 55016255261055 |
11 | 165912989078a0 |
12 | 62066286a3593 |
13 | 249101a4056ba |
14 | d82b2dbab54b |
15 | 656174499e20 |
hex | 3209785a097f |
55016255261055 has 32 divisors (see below), whose sum is σ = 96063952838400. Its totient is φ = 26664664666880.
The previous prime is 55016255260999. The next prime is 55016255261137.
55016255261055 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 55016255261055 - 27 = 55016255260927 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 55016255260995 and 55016255261013.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 61324182 + ... + 62214851.
It is an arithmetic number, because the mean of its divisors is an integer number (3001998526200).
Almost surely, 255016255261055 is an apocalyptic number.
55016255261055 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
55016255261055 is a deficient number, since it is larger than the sum of its proper divisors (41047697577345).
55016255261055 is a wasteful number, since it uses less digits than its factorization.
55016255261055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 123541751.
The product of its (nonzero) digits is 2250000, while the sum is 48.
The spelling of 55016255261055 in words is "fifty-five trillion, sixteen billion, two hundred fifty-five million, two hundred sixty-one thousand, fifty-five".
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