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5502132312055 = 51100426462411
BaseRepresentation
bin101000000010001000010…
…1001000101011111110111
3201110222222001122111220021
41100010100221011133313
51210121331332441210
615411351130350011
71105341652663651
oct120042051053767
921428861574807
105502132312055
111831494282625
1274a424b8b307
1330bb05c04342
14150439c676d1
15981ca650bda
hex50110a457f7

5502132312055 has 4 divisors (see below), whose sum is σ = 6602558774472. Its totient is φ = 4401705849640.

The previous prime is 5502132312049. The next prime is 5502132312107.

5502132312055 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 5502132312055 - 217 = 5502132180983 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 5502132312055.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 550213231201 + ... + 550213231210.

It is an arithmetic number, because the mean of its divisors is an integer number (1650639693618).

Almost surely, 25502132312055 is an apocalyptic number.

5502132312055 is a deficient number, since it is larger than the sum of its proper divisors (1100426462417).

5502132312055 is a wasteful number, since it uses less digits than its factorization.

5502132312055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1100426462416.

The product of its (nonzero) digits is 45000, while the sum is 34.

The spelling of 5502132312055 in words is "five trillion, five hundred two billion, one hundred thirty-two million, three hundred twelve thousand, fifty-five".

Divisors: 1 5 1100426462411 5502132312055