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55033324403 = 131420101713
BaseRepresentation
bin110011010000001111…
…011110001101110011
312021001100220112200012
4303100033132031303
51400202012340103
641140523045135
73655530352631
oct632017361563
9167040815605
1055033324403
1121380971192
12a7ba6707ab
1352607987a5
142940dc8351
1516716d02d8
hexcd03de373

55033324403 has 4 divisors (see below), whose sum is σ = 55453426248. Its totient is φ = 54613222560.

The previous prime is 55033324369. The next prime is 55033324417. The reversal of 55033324403 is 30442333055.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30442333055 = 56088466611.

It is a cyclic number.

It is not a de Polignac number, because 55033324403 - 220 = 55032275827 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 55033324403.

It is not an unprimeable number, because it can be changed into a prime (55033324483) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 210050726 + ... + 210050987.

It is an arithmetic number, because the mean of its divisors is an integer number (13863356562).

Almost surely, 255033324403 is an apocalyptic number.

55033324403 is a deficient number, since it is larger than the sum of its proper divisors (420101845).

55033324403 is a wasteful number, since it uses less digits than its factorization.

55033324403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 420101844.

The product of its (nonzero) digits is 64800, while the sum is 32.

Adding to 55033324403 its reverse (30442333055), we get a palindrome (85475657458).

The spelling of 55033324403 in words is "fifty-five billion, thirty-three million, three hundred twenty-four thousand, four hundred three".

Divisors: 1 131 420101713 55033324403