Base | Representation |
---|---|
bin | 111110100100010001011100… |
… | …0100010100100111100010111 |
3 | 2200011121021112200202102022221 |
4 | 1331020202320202210330113 |
5 | 1034113310004012342330 |
6 | 5230252032354203211 |
7 | 223630654133342455 |
oct | 17510427042447427 |
9 | 2604537480672287 |
10 | 550343025512215 |
11 | 14a3a1191541311 |
12 | 518841b9883507 |
13 | 1a811180a42720 |
14 | 99c8a5d0db9d5 |
15 | 4395a42136b7a |
hex | 1f488b88a4f17 |
550343025512215 has 32 divisors (see below), whose sum is σ = 722150038794240. Its totient is φ = 400162568091264.
The previous prime is 550343025512191. The next prime is 550343025512233. The reversal of 550343025512215 is 512215520343055.
It is a cyclic number.
It is not a de Polignac number, because 550343025512215 - 239 = 549793269698327 is a prime.
It is a super-2 number, since 2×5503430255122152 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 18469429 + ... + 37971118.
It is an arithmetic number, because the mean of its divisors is an integer number (22567188712320).
Almost surely, 2550343025512215 is an apocalyptic number.
550343025512215 is a deficient number, since it is larger than the sum of its proper divisors (171807013282025).
550343025512215 is a wasteful number, since it uses less digits than its factorization.
550343025512215 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56442871.
The product of its (nonzero) digits is 900000, while the sum is 43.
The spelling of 550343025512215 in words is "five hundred fifty trillion, three hundred forty-three billion, twenty-five million, five hundred twelve thousand, two hundred fifteen".
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