Base | Representation |
---|---|
bin | 110011010000110011… |
… | …011111010010101001 |
3 | 12021002000200020002201 |
4 | 303100303133102221 |
5 | 1400211422002433 |
6 | 41141501300201 |
7 | 3656003535265 |
oct | 632063372251 |
9 | 167060606081 |
10 | 55042765993 |
11 | 2138622a856 |
12 | a801864661 |
13 | 5262723127 |
14 | 29423650a5 |
15 | 1672447a7d |
hex | cd0cdf4a9 |
55042765993 has 2 divisors, whose sum is σ = 55042765994. Its totient is φ = 55042765992.
The previous prime is 55042765961. The next prime is 55042766017. The reversal of 55042765993 is 39956724055.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 39407014144 + 15635751849 = 198512^2 + 125043^2 .
It is a cyclic number.
It is not a de Polignac number, because 55042765993 - 25 = 55042765961 is a prime.
It is not a weakly prime, because it can be changed into another prime (55042765933) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27521382996 + 27521382997.
It is an arithmetic number, because the mean of its divisors is an integer number (27521382997).
Almost surely, 255042765993 is an apocalyptic number.
It is an amenable number.
55042765993 is a deficient number, since it is larger than the sum of its proper divisors (1).
55042765993 is an equidigital number, since it uses as much as digits as its factorization.
55042765993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10206000, while the sum is 55.
The spelling of 55042765993 in words is "fifty-five billion, forty-two million, seven hundred sixty-five thousand, nine hundred ninety-three".
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