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550428074033 is a prime number
BaseRepresentation
bin10000000001010000001…
…00011110000000110001
31221121202021112022001012
420000220010132000301
533004234041332113
61100510235520305
754524056301345
oct10005004360061
91847667468035
10550428074033
111a2487330942
128a8152b9095
133cb9c7ab536
141c8d8745625
15e4b7d84aa8
hex802811e031

550428074033 has 2 divisors, whose sum is σ = 550428074034. Its totient is φ = 550428074032.

The previous prime is 550428074003. The next prime is 550428074071. The reversal of 550428074033 is 330470824055.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 544956956944 + 5471117089 = 738212^2 + 73967^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-550428074033 is a prime.

It is not a weakly prime, because it can be changed into another prime (550428074003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275214037016 + 275214037017.

It is an arithmetic number, because the mean of its divisors is an integer number (275214037017).

Almost surely, 2550428074033 is an apocalyptic number.

It is an amenable number.

550428074033 is a deficient number, since it is larger than the sum of its proper divisors (1).

550428074033 is an equidigital number, since it uses as much as digits as its factorization.

550428074033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 403200, while the sum is 41.

Adding to 550428074033 its reverse (330470824055), we get a palindrome (880898898088).

The spelling of 550428074033 in words is "five hundred fifty billion, four hundred twenty-eight million, seventy-four thousand, thirty-three".