Base | Representation |
---|---|
bin | 10000000001010000110… |
… | …00011111110100000011 |
3 | 1221121202122102001001012 |
4 | 20000220120133310003 |
5 | 33004241412334131 |
6 | 1100510544231135 |
7 | 54524152026254 |
oct | 10005030376403 |
9 | 1847678361035 |
10 | 550433324291 |
11 | 1a248a2974a4 |
12 | 8a81700b4ab |
13 | 3cba08c91b6 |
14 | 1c8d9310b2b |
15 | e4b857052b |
hex | 802861fd03 |
550433324291 has 2 divisors, whose sum is σ = 550433324292. Its totient is φ = 550433324290.
The previous prime is 550433324251. The next prime is 550433324323. The reversal of 550433324291 is 192423334055.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 550433324291 - 230 = 549359582467 is a prime.
It is not a weakly prime, because it can be changed into another prime (550433324251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275216662145 + 275216662146.
It is an arithmetic number, because the mean of its divisors is an integer number (275216662146).
Almost surely, 2550433324291 is an apocalyptic number.
550433324291 is a deficient number, since it is larger than the sum of its proper divisors (1).
550433324291 is an equidigital number, since it uses as much as digits as its factorization.
550433324291 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 388800, while the sum is 41.
The spelling of 550433324291 in words is "five hundred fifty billion, four hundred thirty-three million, three hundred twenty-four thousand, two hundred ninety-one".
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