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5504334881 is a prime number
BaseRepresentation
bin1010010000001010…
…10111110000100001
3112012121101011221212
411020011113300201
542233102204011
62310104555505
7253255034363
oct51005276041
915177334855
105504334881
1123750652a1
121097482b95
136994a0ab6
143a3064d33
1522337908b
hex148157c21

5504334881 has 2 divisors, whose sum is σ = 5504334882. Its totient is φ = 5504334880.

The previous prime is 5504334833. The next prime is 5504334889. The reversal of 5504334881 is 1884334055.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4548288481 + 956046400 = 67441^2 + 30920^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5504334881 is a prime.

It is a super-2 number, since 2×55043348812 = 60595404964386568322, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5504334889) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2752167440 + 2752167441.

It is an arithmetic number, because the mean of its divisors is an integer number (2752167441).

Almost surely, 25504334881 is an apocalyptic number.

It is an amenable number.

5504334881 is a deficient number, since it is larger than the sum of its proper divisors (1).

5504334881 is an equidigital number, since it uses as much as digits as its factorization.

5504334881 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 230400, while the sum is 41.

The square root of 5504334881 is about 74191.2048763194. The cubic root of 5504334881 is about 1765.6377925451.

The spelling of 5504334881 in words is "five billion, five hundred four million, three hundred thirty-four thousand, eight hundred eighty-one".