Base | Representation |
---|---|
bin | 110011010000110101… |
… | …110100010011001101 |
3 | 12021002001211020022220 |
4 | 303100311310103031 |
5 | 1400212101020313 |
6 | 41141522325553 |
7 | 3656011656561 |
oct | 632065642315 |
9 | 167061736286 |
10 | 55043376333 |
11 | 21386607370 |
12 | a801ab98b9 |
13 | 52628a7b8a |
14 | 29424836a1 |
15 | 1672518823 |
hex | cd0d744cd |
55043376333 has 32 divisors (see below), whose sum is σ = 84295080960. Its totient is φ = 31597050240.
The previous prime is 55043376301. The next prime is 55043376343. The reversal of 55043376333 is 33367334055.
55043376333 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 55043376333 - 25 = 55043376301 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55043376343) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5156760 + ... + 5167422.
It is an arithmetic number, because the mean of its divisors is an integer number (2634221280).
Almost surely, 255043376333 is an apocalyptic number.
It is an amenable number.
55043376333 is a deficient number, since it is larger than the sum of its proper divisors (29251704627).
55043376333 is a wasteful number, since it uses less digits than its factorization.
55043376333 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18929.
The product of its (nonzero) digits is 1020600, while the sum is 42.
The spelling of 55043376333 in words is "fifty-five billion, forty-three million, three hundred seventy-six thousand, three hundred thirty-three".
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