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55043450143 = 115003950013
BaseRepresentation
bin110011010000110110…
…000110010100011111
312021002001221222120121
4303100312012110133
51400212110401033
641141524055411
73656012415013
oct632066062437
9167061858517
1055043450143
1121386657870
12a801b34567
135262902656
1429424a2543
15167253062d
hexcd0d8651f

55043450143 has 4 divisors (see below), whose sum is σ = 60047400168. Its totient is φ = 50039500120.

The previous prime is 55043450123. The next prime is 55043450171. The reversal of 55043450143 is 34105434055.

55043450143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-55043450143 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 55043450099 and 55043450108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55043450113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2501974996 + ... + 2501975017.

It is an arithmetic number, because the mean of its divisors is an integer number (15011850042).

Almost surely, 255043450143 is an apocalyptic number.

55043450143 is a deficient number, since it is larger than the sum of its proper divisors (5003950025).

55043450143 is a wasteful number, since it uses less digits than its factorization.

55043450143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5003950024.

The product of its (nonzero) digits is 72000, while the sum is 34.

Adding to 55043450143 its reverse (34105434055), we get a palindrome (89148884198).

The spelling of 55043450143 in words is "fifty-five billion, forty-three million, four hundred fifty thousand, one hundred forty-three".

Divisors: 1 11 5003950013 55043450143