Base | Representation |
---|---|
bin | 110011010000111001… |
… | …011101001100000101 |
3 | 12021002010121200211222 |
4 | 303100321131030011 |
5 | 1400212322031440 |
6 | 41141555010125 |
7 | 3656023041632 |
oct | 632071351405 |
9 | 167063550758 |
10 | 55044330245 |
11 | 213870a9023 |
12 | a802299945 |
13 | 5262b50118 |
14 | 2942651189 |
15 | 16726562b5 |
hex | cd0e5d305 |
55044330245 has 4 divisors (see below), whose sum is σ = 66053196300. Its totient is φ = 44035464192.
The previous prime is 55044330241. The next prime is 55044330287. The reversal of 55044330245 is 54203344055.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 33480582529 + 21563747716 = 182977^2 + 146846^2 .
It is a cyclic number.
It is not a de Polignac number, because 55044330245 - 22 = 55044330241 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55044330241) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5504433020 + ... + 5504433029.
It is an arithmetic number, because the mean of its divisors is an integer number (16513299075).
Almost surely, 255044330245 is an apocalyptic number.
It is an amenable number.
55044330245 is a deficient number, since it is larger than the sum of its proper divisors (11008866055).
55044330245 is a wasteful number, since it uses less digits than its factorization.
55044330245 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11008866054.
The product of its (nonzero) digits is 144000, while the sum is 35.
The spelling of 55044330245 in words is "fifty-five billion, forty-four million, three hundred thirty thousand, two hundred forty-five".
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