Base | Representation |
---|---|
bin | 110011010000111001… |
… | …011101001100000001 |
3 | 12021002010121200211211 |
4 | 303100321131030001 |
5 | 1400212322031431 |
6 | 41141555010121 |
7 | 3656023041625 |
oct | 632071351401 |
9 | 167063550754 |
10 | 55044330241 |
11 | 213870a901a |
12 | a802299941 |
13 | 5262b50114 |
14 | 2942651185 |
15 | 16726562b1 |
hex | cd0e5d301 |
55044330241 has 2 divisors, whose sum is σ = 55044330242. Its totient is φ = 55044330240.
The previous prime is 55044330239. The next prime is 55044330287. The reversal of 55044330241 is 14203344055.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 50084649616 + 4959680625 = 223796^2 + 70425^2 .
It is a cyclic number.
It is not a de Polignac number, because 55044330241 - 21 = 55044330239 is a prime.
Together with 55044330239, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (55044730241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27522165120 + 27522165121.
It is an arithmetic number, because the mean of its divisors is an integer number (27522165121).
Almost surely, 255044330241 is an apocalyptic number.
It is an amenable number.
55044330241 is a deficient number, since it is larger than the sum of its proper divisors (1).
55044330241 is an equidigital number, since it uses as much as digits as its factorization.
55044330241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28800, while the sum is 31.
Adding to 55044330241 its reverse (14203344055), we get a palindrome (69247674296).
The spelling of 55044330241 in words is "fifty-five billion, forty-four million, three hundred thirty thousand, two hundred forty-one".
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