Base | Representation |
---|---|
bin | 110011010001010000… |
… | …100000101100100001 |
3 | 12021002112222202012211 |
4 | 303101100200230201 |
5 | 1400220343431141 |
6 | 41142332322121 |
7 | 3656125312654 |
oct | 632120405441 |
9 | 167075882184 |
10 | 55050373921 |
11 | 2138a5567a4 |
12 | a804313341 |
13 | 5264187c6a |
14 | 294338589b |
15 | 1672e4bd81 |
hex | cd1420b21 |
55050373921 has 2 divisors, whose sum is σ = 55050373922. Its totient is φ = 55050373920.
The previous prime is 55050373871. The next prime is 55050373943. The reversal of 55050373921 is 12937305055.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 53091072225 + 1959301696 = 230415^2 + 44264^2 .
It is a cyclic number.
It is not a de Polignac number, because 55050373921 - 29 = 55050373409 is a prime.
It is not a weakly prime, because it can be changed into another prime (55050373951) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27525186960 + 27525186961.
It is an arithmetic number, because the mean of its divisors is an integer number (27525186961).
Almost surely, 255050373921 is an apocalyptic number.
It is an amenable number.
55050373921 is a deficient number, since it is larger than the sum of its proper divisors (1).
55050373921 is an equidigital number, since it uses as much as digits as its factorization.
55050373921 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 141750, while the sum is 40.
Adding to 55050373921 its reverse (12937305055), we get a palindrome (67987678976).
The spelling of 55050373921 in words is "fifty-five billion, fifty million, three hundred seventy-three thousand, nine hundred twenty-one".
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