Base | Representation |
---|---|
bin | 11001000010001011101000… |
… | …11110101111100011101011 |
3 | 21012220210002111002221120012 |
4 | 30201011310132233203223 |
5 | 24203422011303032003 |
6 | 313025512404522135 |
7 | 14411161643463365 |
oct | 1441056436574353 |
9 | 235823074087505 |
10 | 55050550049003 |
11 | 165a4897379653 |
12 | 62111b99b034b |
13 | 24943244b3832 |
14 | d84664783d35 |
15 | 656ed01788d8 |
hex | 3211747af8eb |
55050550049003 has 2 divisors, whose sum is σ = 55050550049004. Its totient is φ = 55050550049002.
The previous prime is 55050550048987. The next prime is 55050550049009. The reversal of 55050550049003 is 30094005505055.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 55050550049003 - 24 = 55050550048987 is a prime.
It is not a weakly prime, because it can be changed into another prime (55050550049009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27525275024501 + 27525275024502.
It is an arithmetic number, because the mean of its divisors is an integer number (27525275024502).
Almost surely, 255050550049003 is an apocalyptic number.
55050550049003 is a deficient number, since it is larger than the sum of its proper divisors (1).
55050550049003 is an equidigital number, since it uses as much as digits as its factorization.
55050550049003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 337500, while the sum is 41.
The spelling of 55050550049003 in words is "fifty-five trillion, fifty billion, five hundred fifty million, forty-nine thousand, three".
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