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550528332433 is a prime number
BaseRepresentation
bin10000000001011100000…
…10111011001010010001
31221122000021011221201021
420000232002323022101
533004440223114213
61100524220435441
754526414421032
oct10005602731221
91848007157637
10550528332433
111a2528989522
128a8429a8b81
133cbb74b2831
141c907ba2a89
15e4c1a8ad8d
hex802e0bb291

550528332433 has 2 divisors, whose sum is σ = 550528332434. Its totient is φ = 550528332432.

The previous prime is 550528332421. The next prime is 550528332437. The reversal of 550528332433 is 334233825055.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 517661543169 + 32866789264 = 719487^2 + 181292^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-550528332433 is a prime.

It is a super-4 number, since 4×5505283324334 (a number of 48 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 550528332433.

It is not a weakly prime, because it can be changed into another prime (550528332437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275264166216 + 275264166217.

It is an arithmetic number, because the mean of its divisors is an integer number (275264166217).

Almost surely, 2550528332433 is an apocalyptic number.

It is an amenable number.

550528332433 is a deficient number, since it is larger than the sum of its proper divisors (1).

550528332433 is an equidigital number, since it uses as much as digits as its factorization.

550528332433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296000, while the sum is 43.

The spelling of 550528332433 in words is "five hundred fifty billion, five hundred twenty-eight million, three hundred thirty-two thousand, four hundred thirty-three".