Base | Representation |
---|---|
bin | 11001000010010100000001… |
… | …11101110010011001101001 |
3 | 21012221012201101222210121221 |
4 | 30201022000331302121221 |
5 | 24204010222421343001 |
6 | 313031535354302041 |
7 | 14411411400513241 |
oct | 1441120075623151 |
9 | 235835641883557 |
10 | 55055054481001 |
11 | 165a6798a77023 |
12 | 6212056427921 |
13 | 249489177c703 |
14 | d84970ac4b21 |
15 | 6571958401a1 |
hex | 321280f72669 |
55055054481001 has 2 divisors, whose sum is σ = 55055054481002. Its totient is φ = 55055054481000.
The previous prime is 55055054480939. The next prime is 55055054481067. The reversal of 55055054481001 is 10018445055055.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 54073962250000 + 981092231001 = 7353500^2 + 990501^2 .
It is a cyclic number.
It is not a de Polignac number, because 55055054481001 - 213 = 55055054472809 is a prime.
It is not a weakly prime, because it can be changed into another prime (55055054481101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27527527240500 + 27527527240501.
It is an arithmetic number, because the mean of its divisors is an integer number (27527527240501).
Almost surely, 255055054481001 is an apocalyptic number.
It is an amenable number.
55055054481001 is a deficient number, since it is larger than the sum of its proper divisors (1).
55055054481001 is an equidigital number, since it uses as much as digits as its factorization.
55055054481001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 400000, while the sum is 43.
The spelling of 55055054481001 in words is "fifty-five trillion, fifty-five billion, fifty-four million, four hundred eighty-one thousand, one".
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