Base | Representation |
---|---|
bin | 11001000010010100000001… |
… | …11110110010011111111011 |
3 | 21012221012201102111010202212 |
4 | 30201022000332302133323 |
5 | 24204010223003243142 |
6 | 313031535404045335 |
7 | 14411411402655545 |
oct | 1441120076623773 |
9 | 235835642433685 |
10 | 55055054743547 |
11 | 165a6799136301 |
12 | 621205653384b |
13 | 2494891842071 |
14 | d84970b52695 |
15 | 657195892d82 |
hex | 321280fb27fb |
55055054743547 has 2 divisors, whose sum is σ = 55055054743548. Its totient is φ = 55055054743546.
The previous prime is 55055054743523. The next prime is 55055054743583. The reversal of 55055054743547 is 74534745055055.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55055054743547 - 26 = 55055054743483 is a prime.
It is not a weakly prime, because it can be changed into another prime (55055054743147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27527527371773 + 27527527371774.
It is an arithmetic number, because the mean of its divisors is an integer number (27527527371774).
Almost surely, 255055054743547 is an apocalyptic number.
55055054743547 is a deficient number, since it is larger than the sum of its proper divisors (1).
55055054743547 is an equidigital number, since it uses as much as digits as its factorization.
55055054743547 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 147000000, while the sum is 59.
The spelling of 55055054743547 in words is "fifty-five trillion, fifty-five billion, fifty-four million, seven hundred forty-three thousand, five hundred forty-seven".
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