Base | Representation |
---|---|
bin | 100000110100001… |
… | …111010100001011 |
3 | 1102100222121101011 |
4 | 200310033110023 |
5 | 2111421041011 |
6 | 130344304351 |
7 | 16433504104 |
oct | 4064172413 |
9 | 1370877334 |
10 | 550565131 |
11 | 262863806 |
12 | 1344720b7 |
13 | 8a0aa7ac |
14 | 531993ab |
15 | 33505621 |
hex | 20d0f50b |
550565131 has 2 divisors, whose sum is σ = 550565132. Its totient is φ = 550565130.
The previous prime is 550565123. The next prime is 550565153. The reversal of 550565131 is 131565055.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 550565131 - 23 = 550565123 is a prime.
It is a super-2 number, since 2×5505651312 = 606243926946094322, which contains 22 as substring.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 550565093 and 550565102.
It is not a weakly prime, because it can be changed into another prime (550565101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275282565 + 275282566.
It is an arithmetic number, because the mean of its divisors is an integer number (275282566).
Almost surely, 2550565131 is an apocalyptic number.
550565131 is a deficient number, since it is larger than the sum of its proper divisors (1).
550565131 is an equidigital number, since it uses as much as digits as its factorization.
550565131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11250, while the sum is 31.
The square root of 550565131 is about 23464.1243390841. The cubic root of 550565131 is about 819.6017950565.
The spelling of 550565131 in words is "five hundred fifty million, five hundred sixty-five thousand, one hundred thirty-one".
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