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55060010059993 is a prime number
BaseRepresentation
bin11001000010011101010000…
…10101110100100011011001
321012221200111202210022000121
430201032220111310203121
524204100400033404433
6313034115221433241
714411645243320351
oct1441165025644331
9235850452708017
1055060010059993
11165a89012a3954
126212bb9b6b821
1324951a1357383
14d84cc0d01b61
1565738591ec2d
hex3213a85748d9

55060010059993 has 2 divisors, whose sum is σ = 55060010059994. Its totient is φ = 55060010059992.

The previous prime is 55060010059949. The next prime is 55060010060051. The reversal of 55060010059993 is 39995001006055.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 50989268018329 + 4070742041664 = 7140677^2 + 2017608^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-55060010059993 is a prime.

It is a super-3 number, since 3×550600100599933 (a number of 42 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 55060010059993.

It is not a weakly prime, because it can be changed into another prime (55060010059393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27530005029996 + 27530005029997.

It is an arithmetic number, because the mean of its divisors is an integer number (27530005029997).

Almost surely, 255060010059993 is an apocalyptic number.

It is an amenable number.

55060010059993 is a deficient number, since it is larger than the sum of its proper divisors (1).

55060010059993 is an equidigital number, since it uses as much as digits as its factorization.

55060010059993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1640250, while the sum is 52.

The spelling of 55060010059993 in words is "fifty-five trillion, sixty billion, ten million, fifty-nine thousand, nine hundred ninety-three".