Base | Representation |
---|---|
bin | 101000000100000000000… |
… | …1011001010111001100111 |
3 | 201111101100010112002201121 |
4 | 1100020000023022321213 |
5 | 1210203044124023303 |
6 | 15413254005034411 |
7 | 1105543361201212 |
oct | 120100013127147 |
9 | 21441303462647 |
10 | 5506151001703 |
11 | 1833166771640 |
12 | 74b1669b5a07 |
13 | 30c2c666a901 |
14 | 1506db884779 |
15 | 983633689bd |
hex | 502002cae67 |
5506151001703 has 8 divisors (see below), whose sum is σ = 6010884426240. Its totient is φ = 5002113284280.
The previous prime is 5506151001683. The next prime is 5506151001707. The reversal of 5506151001703 is 3071001516055.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5506151001703 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5506151001707) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 173910225 + ... + 173941882.
It is an arithmetic number, because the mean of its divisors is an integer number (751360553280).
Almost surely, 25506151001703 is an apocalyptic number.
5506151001703 is a deficient number, since it is larger than the sum of its proper divisors (504733424537).
5506151001703 is a wasteful number, since it uses less digits than its factorization.
5506151001703 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 347853557.
The product of its (nonzero) digits is 15750, while the sum is 34.
Adding to 5506151001703 its reverse (3071001516055), we get a palindrome (8577152517758).
The spelling of 5506151001703 in words is "five trillion, five hundred six billion, one hundred fifty-one million, one thousand, seven hundred three".
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