Base | Representation |
---|---|
bin | 101000000101010100000… |
… | …0010100111110101100001 |
3 | 201111122121101221120021012 |
4 | 1100022220002213311201 |
5 | 1210224331114130332 |
6 | 15414441252510305 |
7 | 1106003226466235 |
oct | 120125002476541 |
9 | 21448541846235 |
10 | 5508967333217 |
11 | 1834381494147 |
12 | 74b81201b395 |
13 | 30c654c9556a |
14 | 1508c791a5c5 |
15 | 9847a72c3b2 |
hex | 502a80a7d61 |
5508967333217 has 2 divisors, whose sum is σ = 5508967333218. Its totient is φ = 5508967333216.
The previous prime is 5508967333189. The next prime is 5508967333277. The reversal of 5508967333217 is 7123337698055.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5496066008161 + 12901325056 = 2344369^2 + 113584^2 .
It is a cyclic number.
It is not a de Polignac number, because 5508967333217 - 242 = 1110920822113 is a prime.
It is not a weakly prime, because it can be changed into another prime (5508967333277) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2754483666608 + 2754483666609.
It is an arithmetic number, because the mean of its divisors is an integer number (2754483666609).
Almost surely, 25508967333217 is an apocalyptic number.
It is an amenable number.
5508967333217 is a deficient number, since it is larger than the sum of its proper divisors (1).
5508967333217 is an equidigital number, since it uses as much as digits as its factorization.
5508967333217 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 28576800, while the sum is 59.
The spelling of 5508967333217 in words is "five trillion, five hundred eight billion, nine hundred sixty-seven million, three hundred thirty-three thousand, two hundred seventeen".
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