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55100125303 = 167473290149
BaseRepresentation
bin110011010100001110…
…010011000001110111
312021020000121101021121
4303110032103001313
51400321113002203
641151310524411
73660301223506
oct632416230167
9167200541247
1055100125303
1121405647743
12a818b06707
135271587152
142949c1683d
1516774c80bd
hexcd4393077

55100125303 has 4 divisors (see below), whose sum is σ = 55103432200. Its totient is φ = 55096818408.

The previous prime is 55100125279. The next prime is 55100125337. The reversal of 55100125303 is 30352100155.

55100125303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 55100125303 - 25 = 55100125271 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55100125373) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1628328 + ... + 1661821.

It is an arithmetic number, because the mean of its divisors is an integer number (13775858050).

Almost surely, 255100125303 is an apocalyptic number.

55100125303 is a deficient number, since it is larger than the sum of its proper divisors (3306897).

55100125303 is a wasteful number, since it uses less digits than its factorization.

55100125303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3306896.

The product of its (nonzero) digits is 2250, while the sum is 25.

Adding to 55100125303 its reverse (30352100155), we get a palindrome (85452225458).

The spelling of 55100125303 in words is "fifty-five billion, one hundred million, one hundred twenty-five thousand, three hundred three".

Divisors: 1 16747 3290149 55100125303