Base | Representation |
---|---|
bin | 101000000101110100011… |
… | …0111111101001010110111 |
3 | 201111202102012200121111020 |
4 | 1100023220313331022313 |
5 | 1210234043043243210 |
6 | 15415141230312223 |
7 | 1106042205126654 |
oct | 120135067751267 |
9 | 21452365617436 |
10 | 5510055056055 |
11 | 183488a483440 |
12 | 74ba76358673 |
13 | 30c799438044 |
14 | 15098c180c2b |
15 | 984e0e8a770 |
hex | 502e8dfd2b7 |
5510055056055 has 64 divisors (see below), whose sum is σ = 9758812248576. Its totient is φ = 2632553280000.
The previous prime is 5510055056047. The next prime is 5510055056083. The reversal of 5510055056055 is 5506505500155.
It is not a de Polignac number, because 5510055056055 - 23 = 5510055056047 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5510055055998 and 5510055056016.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2732817 + ... + 4299813.
It is an arithmetic number, because the mean of its divisors is an integer number (152481441384).
Almost surely, 25510055056055 is an apocalyptic number.
5510055056055 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
5510055056055 is a deficient number, since it is larger than the sum of its proper divisors (4248757192521).
5510055056055 is a wasteful number, since it uses less digits than its factorization.
5510055056055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1567328.
The product of its (nonzero) digits is 468750, while the sum is 42.
It can be divided in two parts, 55100 and 55056055, that added together give a palindrome (55111155).
The spelling of 5510055056055 in words is "five trillion, five hundred ten billion, fifty-five million, fifty-six thousand, fifty-five".
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