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55103131 is a prime number
BaseRepresentation
bin1101001000110…
…0111010011011
310211200112021201
43102030322123
5103101300011
65245015031
71236240346
oct322147233
9124615251
1055103131
1129116886
1216554477
13b554105
14746545d
154c86cc1
hex348ce9b

55103131 has 2 divisors, whose sum is σ = 55103132. Its totient is φ = 55103130.

The previous prime is 55103117. The next prime is 55103143. The reversal of 55103131 is 13130155.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 55103131 - 25 = 55103099 is a prime.

It is a super-2 number, since 2×551031312 = 6072710092006322, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 55103099 and 55103108.

It is not a weakly prime, because it can be changed into another prime (55103231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27551565 + 27551566.

It is an arithmetic number, because the mean of its divisors is an integer number (27551566).

Almost surely, 255103131 is an apocalyptic number.

55103131 is a deficient number, since it is larger than the sum of its proper divisors (1).

55103131 is an equidigital number, since it uses as much as digits as its factorization.

55103131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 225, while the sum is 19.

The square root of 55103131 is about 7423.1483212987. The cubic root of 55103131 is about 380.5327960183.

Adding to 55103131 its reverse (13130155), we get a palindrome (68233286).

The spelling of 55103131 in words is "fifty-five million, one hundred three thousand, one hundred thirty-one".