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551034134377 is a prime number
BaseRepresentation
bin10000000010011000011…
…00011001111101101001
31221200022111221100112121
420001030030121331221
533012004214300002
61101050325511241
754545065601206
oct10011414317551
91850274840477
10551034134377
111a2768448a61
128a964272521
133cc6821971c
141c955028cad
15e50119d237
hex804c319f69

551034134377 has 2 divisors, whose sum is σ = 551034134378. Its totient is φ = 551034134376.

The previous prime is 551034134323. The next prime is 551034134381. The reversal of 551034134377 is 773431430155.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 486895532841 + 64138601536 = 697779^2 + 253256^2 .

It is a cyclic number.

It is not a de Polignac number, because 551034134377 - 211 = 551034132329 is a prime.

It is not a weakly prime, because it can be changed into another prime (551034134177) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275517067188 + 275517067189.

It is an arithmetic number, because the mean of its divisors is an integer number (275517067189).

Almost surely, 2551034134377 is an apocalyptic number.

It is an amenable number.

551034134377 is a deficient number, since it is larger than the sum of its proper divisors (1).

551034134377 is an equidigital number, since it uses as much as digits as its factorization.

551034134377 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 529200, while the sum is 43.

The spelling of 551034134377 in words is "five hundred fifty-one billion, thirty-four million, one hundred thirty-four thousand, three hundred seventy-seven".