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551095314433 is a prime number
BaseRepresentation
bin10000000010011111101…
…01110010100000000001
31221200110210001121210121
420001033311302200001
533012120400030213
61101100353100241
754546440611546
oct10011765624001
91850423047717
10551095314433
111a2799a35494
128a980857681
133cc77aba841
141c95d1d2bcd
15e50673588d
hex804fd72801

551095314433 has 2 divisors, whose sum is σ = 551095314434. Its totient is φ = 551095314432.

The previous prime is 551095314421. The next prime is 551095314439. The reversal of 551095314433 is 334413590155.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 462608103409 + 88487211024 = 680153^2 + 297468^2 .

It is a cyclic number.

It is not a de Polignac number, because 551095314433 - 25 = 551095314401 is a prime.

It is a super-2 number, since 2×5510953144332 (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 551095314433.

It is not a weakly prime, because it can be changed into another prime (551095314439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275547657216 + 275547657217.

It is an arithmetic number, because the mean of its divisors is an integer number (275547657217).

Almost surely, 2551095314433 is an apocalyptic number.

It is an amenable number.

551095314433 is a deficient number, since it is larger than the sum of its proper divisors (1).

551095314433 is an equidigital number, since it uses as much as digits as its factorization.

551095314433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 486000, while the sum is 43.

The spelling of 551095314433 in words is "five hundred fifty-one billion, ninety-five million, three hundred fourteen thousand, four hundred thirty-three".