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55111139957 = 78203704719
BaseRepresentation
bin110011010100111000…
…010100001001110101
312021020210022222112202
4303110320110021311
51400331422434312
641152342554245
73660463650266
oct632470241165
9167223288482
1055111139957
1121410890165
12a820738985
1352739427b3
14294b48296d
1516784519c2
hexcd4e14275

55111139957 has 4 divisors (see below), whose sum is σ = 55111922880. Its totient is φ = 55110357036.

The previous prime is 55111139929. The next prime is 55111139959. The reversal of 55111139957 is 75993111155.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 55111139957 - 212 = 55111135861 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55111139959) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 274157 + ... + 430562.

It is an arithmetic number, because the mean of its divisors is an integer number (13777980720).

Almost surely, 255111139957 is an apocalyptic number.

It is an amenable number.

55111139957 is a deficient number, since it is larger than the sum of its proper divisors (782923).

55111139957 is an equidigital number, since it uses as much as digits as its factorization.

55111139957 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 782922.

The product of its digits is 212625, while the sum is 47.

The spelling of 55111139957 in words is "fifty-five billion, one hundred eleven million, one hundred thirty-nine thousand, nine hundred fifty-seven".

Divisors: 1 78203 704719 55111139957