Base | Representation |
---|---|
bin | 101000000110010101001… |
… | …1101000111001000100001 |
3 | 201111212020220000120100011 |
4 | 1100030222131013020201 |
5 | 1210243321230041413 |
6 | 15415442332524521 |
7 | 1106111365152451 |
oct | 120145235071041 |
9 | 21455226016304 |
10 | 5511155315233 |
11 | 18352a4555447 |
12 | 750122920741 |
13 | 30c913379989 |
14 | 150a54349d61 |
15 | 9855787333d |
hex | 5032a747221 |
5511155315233 has 2 divisors, whose sum is σ = 5511155315234. Its totient is φ = 5511155315232.
The previous prime is 5511155315219. The next prime is 5511155315269. The reversal of 5511155315233 is 3325135511155.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4458208433809 + 1052946881424 = 2111447^2 + 1026132^2 .
It is a cyclic number.
It is not a de Polignac number, because 5511155315233 - 225 = 5511121760801 is a prime.
It is not a weakly prime, because it can be changed into another prime (5511155315213) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2755577657616 + 2755577657617.
It is an arithmetic number, because the mean of its divisors is an integer number (2755577657617).
Almost surely, 25511155315233 is an apocalyptic number.
It is an amenable number.
5511155315233 is a deficient number, since it is larger than the sum of its proper divisors (1).
5511155315233 is an equidigital number, since it uses as much as digits as its factorization.
5511155315233 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 168750, while the sum is 40.
The spelling of 5511155315233 in words is "five trillion, five hundred eleven billion, one hundred fifty-five million, three hundred fifteen thousand, two hundred thirty-three".
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