Base | Representation |
---|---|
bin | 11001000011111110011111… |
… | …01101111110101101101111 |
3 | 21020010200020200202212001021 |
4 | 30201333033231332231233 |
5 | 24210424301314441142 |
6 | 313114111102155011 |
7 | 14415503643202210 |
oct | 1441771755765557 |
9 | 236120220685037 |
10 | 55112210312047 |
11 | 16618a58a48929 |
12 | 6221147882a67 |
13 | 249a09cbb6395 |
14 | d87633937407 |
15 | 6588dd531267 |
hex | 321fcfb7eb6f |
55112210312047 has 16 divisors (see below), whose sum is σ = 65159210318400. Its totient is φ = 45608762949120.
The previous prime is 55112210312041. The next prime is 55112210312099. The reversal of 55112210312047 is 74021301221155.
It is not a de Polignac number, because 55112210312047 - 231 = 55110062828399 is a prime.
It is a super-2 number, since 2×551122103120472 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55112210312041) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2950797 + ... + 10905577.
It is an arithmetic number, because the mean of its divisors is an integer number (4072450644900).
Almost surely, 255112210312047 is an apocalyptic number.
55112210312047 is a deficient number, since it is larger than the sum of its proper divisors (10047000006353).
55112210312047 is a wasteful number, since it uses less digits than its factorization.
55112210312047 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7988946.
The product of its (nonzero) digits is 16800, while the sum is 34.
The spelling of 55112210312047 in words is "fifty-five trillion, one hundred twelve billion, two hundred ten million, three hundred twelve thousand, forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.083 sec. • engine limits •