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55112643965 = 511022528793
BaseRepresentation
bin110011010100111110…
…000011010101111101
312021020220011101122202
4303110332003111331
51400332314101330
641152435121245
73660512513201
oct632476032575
9167226141582
1055112643965
1121411718145
12a821143225
13527404b242
14294b754b01
15167864c445
hexcd4f8357d

55112643965 has 4 divisors (see below), whose sum is σ = 66135172764. Its totient is φ = 44090115168.

The previous prime is 55112643941. The next prime is 55112643967. The reversal of 55112643965 is 56934621155.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 21387892516 + 33724751449 = 146246^2 + 183643^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-55112643965 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55112643967) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5511264392 + ... + 5511264401.

It is an arithmetic number, because the mean of its divisors is an integer number (16533793191).

Almost surely, 255112643965 is an apocalyptic number.

It is an amenable number.

55112643965 is a deficient number, since it is larger than the sum of its proper divisors (11022528799).

55112643965 is a wasteful number, since it uses less digits than its factorization.

55112643965 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11022528798.

The product of its digits is 972000, while the sum is 47.

The spelling of 55112643965 in words is "fifty-five billion, one hundred twelve million, six hundred forty-three thousand, nine hundred sixty-five".

Divisors: 1 5 11022528793 55112643965