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551131001 is a prime number
BaseRepresentation
bin100000110110011…
…001011101111001
31102102001100121022
4200312121131321
52112042143001
6130404352225
716441351631
oct4066313571
91372040538
10551131001
1126310a973
121346a5675
138a248225
14532a56c1
15335b811b
hex20d99779

551131001 has 2 divisors, whose sum is σ = 551131002. Its totient is φ = 551131000.

The previous prime is 551130971. The next prime is 551131019. The reversal of 551131001 is 100131155.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 442471225 + 108659776 = 21035^2 + 10424^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-551131001 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (551131601) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275565500 + 275565501.

It is an arithmetic number, because the mean of its divisors is an integer number (275565501).

Almost surely, 2551131001 is an apocalyptic number.

It is an amenable number.

551131001 is a deficient number, since it is larger than the sum of its proper divisors (1).

551131001 is an equidigital number, since it uses as much as digits as its factorization.

551131001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 75, while the sum is 17.

The square root of 551131001 is about 23476.1794378898. The cubic root of 551131001 is about 819.8824940684.

Adding to 551131001 its reverse (100131155), we get a palindrome (651262156).

The spelling of 551131001 in words is "five hundred fifty-one million, one hundred thirty-one thousand, one".