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55113145 = 511022629
BaseRepresentation
bin1101001000111…
…1010110111001
310211201001000121
43102033112321
5103102110040
65245133241
71236311503
oct322172671
9124631017
1055113145
112912335a
121655a221
13b558839
147468d73
154c89c4a
hex348f5b9

55113145 has 4 divisors (see below), whose sum is σ = 66135780. Its totient is φ = 44090512.

The previous prime is 55113119. The next prime is 55113181. The reversal of 55113145 is 54131155.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 35141184 + 19971961 = 5928^2 + 4469^2 .

It is a cyclic number.

It is not a de Polignac number, because 55113145 - 223 = 46724537 is a prime.

It is a super-3 number, since 3×551131453 (a number of 24 digits) contains 333 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5511310 + ... + 5511319.

It is an arithmetic number, because the mean of its divisors is an integer number (16533945).

Almost surely, 255113145 is an apocalyptic number.

It is an amenable number.

55113145 is a deficient number, since it is larger than the sum of its proper divisors (11022635).

55113145 is a wasteful number, since it uses less digits than its factorization.

55113145 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11022634.

The product of its digits is 1500, while the sum is 25.

The square root of 55113145 is about 7423.8228023034. The cubic root of 55113145 is about 380.5558462790. Note that the first 3 decimals are identical.

The spelling of 55113145 in words is "fifty-five million, one hundred thirteen thousand, one hundred forty-five".

Divisors: 1 5 11022629 55113145