Base | Representation |
---|---|
bin | 110011010101000000… |
… | …100100110111011001 |
3 | 12021020221102000012022 |
4 | 303111000210313121 |
5 | 1400333001234221 |
6 | 41152501224225 |
7 | 3660521240066 |
oct | 632500446731 |
9 | 167227360168 |
10 | 55113305561 |
11 | 2141202a216 |
12 | a821402075 |
13 | 5274220412 |
14 | 294b887c6d |
15 | 167872d4ab |
hex | cd5024dd9 |
55113305561 has 2 divisors, whose sum is σ = 55113305562. Its totient is φ = 55113305560.
The previous prime is 55113305449. The next prime is 55113305573. The reversal of 55113305561 is 16550331155.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 48860449936 + 6252855625 = 221044^2 + 79075^2 .
It is a cyclic number.
It is not a de Polignac number, because 55113305561 - 214 = 55113289177 is a prime.
It is not a weakly prime, because it can be changed into another prime (55113305161) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27556652780 + 27556652781.
It is an arithmetic number, because the mean of its divisors is an integer number (27556652781).
Almost surely, 255113305561 is an apocalyptic number.
It is an amenable number.
55113305561 is a deficient number, since it is larger than the sum of its proper divisors (1).
55113305561 is an equidigital number, since it uses as much as digits as its factorization.
55113305561 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 33750, while the sum is 35.
The spelling of 55113305561 in words is "fifty-five billion, one hundred thirteen million, three hundred five thousand, five hundred sixty-one".
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