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55114315414241 is a prime number
BaseRepresentation
bin11001000100000010011010…
…01100010011101011100001
321020010212200101220010101012
430202001031030103223201
524210443104221223431
6313115100021550305
714415610054236326
oct1442011514235341
9236125611803335
1055114315414241
1116619939251306
126221634875395
13249a34706c695
14d87793350b4d
156589b325522b
hex32204d313ae1

55114315414241 has 2 divisors, whose sum is σ = 55114315414242. Its totient is φ = 55114315414240.

The previous prime is 55114315414199. The next prime is 55114315414253. The reversal of 55114315414241 is 14241451341155.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 37326039126016 + 17788276288225 = 6109504^2 + 4217615^2 .

It is a cyclic number.

It is not a de Polignac number, because 55114315414241 - 210 = 55114315413217 is a prime.

It is not a weakly prime, because it can be changed into another prime (55114315414441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27557157707120 + 27557157707121.

It is an arithmetic number, because the mean of its divisors is an integer number (27557157707121).

Almost surely, 255114315414241 is an apocalyptic number.

It is an amenable number.

55114315414241 is a deficient number, since it is larger than the sum of its proper divisors (1).

55114315414241 is an equidigital number, since it uses as much as digits as its factorization.

55114315414241 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 192000, while the sum is 41.

Adding to 55114315414241 its reverse (14241451341155), we get a palindrome (69355766755396).

The spelling of 55114315414241 in words is "fifty-five trillion, one hundred fourteen billion, three hundred fifteen million, four hundred fourteen thousand, two hundred forty-one".