Base | Representation |
---|---|
bin | 101000000110110000000… |
… | …1101011001100100100001 |
3 | 201111221120202000100011121 |
4 | 1100031200031121210201 |
5 | 1210302143113303423 |
6 | 15420112030412241 |
7 | 1106142625600351 |
oct | 120154015314441 |
9 | 21457522010147 |
10 | 5512057166113 |
11 | 1835717631353 |
12 | 750334961081 |
13 | 30ca28170954 |
14 | 150adc028b61 |
15 | 985abb1845d |
hex | 50360359921 |
5512057166113 has 2 divisors, whose sum is σ = 5512057166114. Its totient is φ = 5512057166112.
The previous prime is 5512057166053. The next prime is 5512057166117. The reversal of 5512057166113 is 3116617502155.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5027227653904 + 484829512209 = 2242148^2 + 696297^2 .
It is a cyclic number.
It is not a de Polignac number, because 5512057166113 - 229 = 5511520295201 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5512057166113.
It is not a weakly prime, because it can be changed into another prime (5512057166117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2756028583056 + 2756028583057.
It is an arithmetic number, because the mean of its divisors is an integer number (2756028583057).
Almost surely, 25512057166113 is an apocalyptic number.
It is an amenable number.
5512057166113 is a deficient number, since it is larger than the sum of its proper divisors (1).
5512057166113 is an equidigital number, since it uses as much as digits as its factorization.
5512057166113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 189000, while the sum is 43.
The spelling of 5512057166113 in words is "five trillion, five hundred twelve billion, fifty-seven million, one hundred sixty-six thousand, one hundred thirteen".
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