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551243455201 is a prime number
BaseRepresentation
bin10000000010110001010…
…10111001101011100001
31221200212002210221201201
420001120222321223201
533012421311031301
61101123204201201
754553220026045
oct10013052715341
91850762727651
10551243455201
111a286561787a
128aa02399201
133cc9c6b83ba
141c974b56025
15e514749201
hex8058ab9ae1

551243455201 has 2 divisors, whose sum is σ = 551243455202. Its totient is φ = 551243455200.

The previous prime is 551243455123. The next prime is 551243455211. The reversal of 551243455201 is 102554342155.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 541673920225 + 9569534976 = 735985^2 + 97824^2 .

It is a cyclic number.

It is not a de Polignac number, because 551243455201 - 27 = 551243455073 is a prime.

It is not a weakly prime, because it can be changed into another prime (551243455211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275621727600 + 275621727601.

It is an arithmetic number, because the mean of its divisors is an integer number (275621727601).

Almost surely, 2551243455201 is an apocalyptic number.

It is an amenable number.

551243455201 is a deficient number, since it is larger than the sum of its proper divisors (1).

551243455201 is an equidigital number, since it uses as much as digits as its factorization.

551243455201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120000, while the sum is 37.

Adding to 551243455201 its reverse (102554342155), we get a palindrome (653797797356).

The spelling of 551243455201 in words is "five hundred fifty-one billion, two hundred forty-three million, four hundred fifty-five thousand, two hundred one".