Base | Representation |
---|---|
bin | 10000000010110001100… |
… | …10011111010000000111 |
3 | 1221200212020112222222202 |
4 | 20001120302133100013 |
5 | 33012422313202403 |
6 | 1101123314545115 |
7 | 54553242651434 |
oct | 10013062372007 |
9 | 1850766488882 |
10 | 551245444103 |
11 | 1a28667560a2 |
12 | 8aa02b9819b |
13 | 3cc9cc33773 |
14 | 1c975112b8b |
15 | e5149dd688 |
hex | 8058c9f407 |
551245444103 has 4 divisors (see below), whose sum is σ = 551248168488. Its totient is φ = 551242719720.
The previous prime is 551245444093. The next prime is 551245444133. The reversal of 551245444103 is 301444542155.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 301444542155 = 5 ⋅60288908431.
It is a cyclic number.
It is not a de Polignac number, because 551245444103 - 26 = 551245444039 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (551245444133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1032008 + ... + 1472253.
It is an arithmetic number, because the mean of its divisors is an integer number (137812042122).
Almost surely, 2551245444103 is an apocalyptic number.
551245444103 is a deficient number, since it is larger than the sum of its proper divisors (2724385).
551245444103 is a wasteful number, since it uses less digits than its factorization.
551245444103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2724384.
The product of its (nonzero) digits is 192000, while the sum is 38.
Adding to 551245444103 its reverse (301444542155), we get a palindrome (852689986258).
The spelling of 551245444103 in words is "five hundred fifty-one billion, two hundred forty-five million, four hundred forty-four thousand, one hundred three".
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