551254031113 has 2 divisors, whose sum is σ = 551254031114. Its totient is φ = 551254031112.

The previous prime is 551254031051. The next prime is 551254031143. The reversal of 551254031113 is 311130452155.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 523013900809 + 28240130304 = 723197^2 + 168048^2 .

It is a cyclic number.

It is not a de Polignac number, because 551254031113 - 2³³ = 542664096521 is a prime.

It is not a weakly prime, because it can be changed into another prime (551254031143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275627015556 + 275627015557.

It is an arithmetic number, because the mean of its divisors is an integer number (275627015557).

Almost surely, 2^551254031113 is an apocalyptic number.

It is an amenable number.

551254031113 is a deficient number, since it is larger than the sum of its proper divisors (1).

551254031113 is an equidigital number, since it uses as much as digits as its factorization.

551254031113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9000, while the sum is 31.

Adding to 551254031113 its reverse (311130452155), we get a palindrome (862384483268).

The spelling of 551254031113 in words is "five hundred fifty-one billion, two hundred fifty-four million, thirty-one thousand, one hundred thirteen".