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55125433324343 = 495711120724899
BaseRepresentation
bin11001000100010111000111…
…10111110001001100110111
321020011221101020012110212102
430202023203313301030313
524211133341412334333
6313124135141212315
714416452425020364
oct1442134367611467
9236157336173772
1055125433324343
1116623623aa3768
12622381810109b
13249b3c953b905
14d88129b5546b
15658e14335ae8
hex3222e3df1337

55125433324343 has 4 divisors (see below), whose sum is σ = 55136554054200. Its totient is φ = 55114312594488.

The previous prime is 55125433324333. The next prime is 55125433324387. The reversal of 55125433324343 is 34342333452155.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-55125433324343 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55125433324303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5560357493 + ... + 5560367406.

It is an arithmetic number, because the mean of its divisors is an integer number (13784138513550).

Almost surely, 255125433324343 is an apocalyptic number.

55125433324343 is a deficient number, since it is larger than the sum of its proper divisors (11120729857).

55125433324343 is a wasteful number, since it uses less digits than its factorization.

55125433324343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11120729856.

The product of its digits is 7776000, while the sum is 47.

Adding to 55125433324343 its reverse (34342333452155), we get a palindrome (89467766776498).

The spelling of 55125433324343 in words is "fifty-five trillion, one hundred twenty-five billion, four hundred thirty-three million, three hundred twenty-four thousand, three hundred forty-three".

Divisors: 1 4957 11120724899 55125433324343